Linked List Cycle II
LeetCode 142
# Definition for singly-linked list.
# class ListNode(object):
# def __init__(self, x):
# self.val = x
# self.next = None
class Solution(object):
def detectCycle(self, head):
"""
:type head: ListNode
:rtype: ListNode
"""
slow = fast = head
while fast and fast.next and fast.next.next:
slow = slow.next
fast = fast.next.next
# 利用 is
if slow is fast:
slow = head
while slow is not fast:
slow = slow.next
fast = fast.next
return slow
return
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